On the recursive sequence x(n+1) = xn-(5k+9)/1+xn-4xn-9 ... xn-(5k+4)

In this paper a solution of the following difference equation was investigated x(n+1) = x(n-(5k+9))/1+x(n-4)x(n-9) ... x(n-(5k+4)), n =0, 1, 2, ... where x(-(5k+9)), x(-(5k+8)), ..., x(-1), x(0) is an element of (0, infinity).